264A - Escape from Stones - CodeForces Solution

constructive algorithms data structures implementation two pointers *1200

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Python Code: 

import os
import sys
import math
from collections import deque, defaultdict
import bisect
import heapq

input = sys.stdin.readline


def multiple():
    a = map(int, input().split())
    return a


def array():
    a = input().split()
    return a


def intarray():
    a = list(map(int, input().split()))
    return a


def intinput():
    n = int(input())
    return n


def strinput():
    s = input().strip()
    return s


def isPrime(n):
    val = int(math.sqrt(n)) + 1
    for i in range(2, val):
        if n % i == 0:
            return False
    return True


def solution():
        MOD = 1000000007
    s = strinput()
    a = [1]
    b = []
    count = 2
    for x in range(len(s)-1):
        i = s[x]
        if i == 'l':
            a.append(count)
        else:
            val = a[-1]
            a.pop()
            a.append(count)
            b.append(val)
        count += 1
    for i in b:
        print(i)
    for i in reversed(range(len(a))):
        print(a[i])
    return


t = 1
for _ in range(t):
        solution()

C++ Code: 

#include <bits/stdc++.h>
using namespace std;

#define endl '\n'
#define _ ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);

int main() { _

    string s; cin >> s;
    int n = s.length();

    vector<int> l;

    for (int i = 0; i < n; i++) {
        if (s[i] == 'l') {
            l.push_back(i+1);
        } else {
            cout << i+1 << endl;
        }
    }

    for (int i = l.size()-1; i >= 0; i--) {
        cout << l[i] << endl;
    }

    return 0;

}


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